Test Case 5

--- Grid dependence ---

Froude number ( Fn ) Reynolds number ( Rn )

0 3.945×10⁶

Figure Number	Items	Remarks
	Grid index used, Integral variables: Coefficients of total resistance (C_T), split into pressure (C_P) and friction (C_F) components, and form factor (1+k) and Uncertainty analysis( U_SN, U_V, E )	Experimental results are available Table U_D = 0.7 [%C_T]
Fig. 5-1	Axial velocity contours and cross flow vectors on the propeller plane (x/Lpp=0.48)
Fig. 5-2	Velocity on the propeller plane (x/Lpp=0.48) at z/Lpp=-0.05	To be compared with experimental results download
Fig. 5-3	Uncertainty analysis of the above item ( U_SN, U_V, E )	U_D = 0.5, 1.0, 1.0 for u, v. w [%U] along the entire cut (proceedings of CFD Wordshop 2000)
Fig. 5-4	Kinematic eddy viscosity ( ν_t ) and longitudinal component of vorticity ( ω _x ) contours on the propeller plane (x / L_PP = 0.48)
Fig. 5-5	Hull surface pressure contours ( port side view )
Fig. 5-6	Hull surface pressure contours ( back view )
Fig. 5-7	Hull surface pressure at x/Lpp = -0.4 and x/Lpp = 0.4	To be compared with experimental results download
Fig. 5-8	Uncertainty analysis of the above item ( U_SN, U_V, E )
Fig. 5-9	Limiting streamlines ( port side view )

Coordinate system or comparisons is fixed to midship on the undisturbed waterplane.
All quantities are non-dimensionalized by density of water ( $\rho$ ), ship speed ( ), and length between perpendiculars ( $L_{PP}$ ):

$\displaystyle F_n$ $\displaystyle = \dfrac{U}{\sqrt{g \cdot L_{PP}}}, \quad R_n = \dfrac{U \cdot L_{PP}}{\nu}$

where is the gravitational acceleration and $\nu$ is the kinematic viscosity.
All CFD predicted force coefficients should be reported using the provided ( Geometry page ) wetted surface area at rest ( $S_{0}$ ). Force coefficients are defined as follows:

$\displaystyle C_{T}$ $\displaystyle = \dfrac{R_{T}}{\frac{1}{2} \rho U^2 S_{0}}, \quad C_{F} = \dfra... ...1}{2} \rho U^2 S_{0}}, \quad C_{P} = \dfrac{R_{P}}{\frac{1}{2} \rho U^2 S_{0}}$

$\displaystyle C_{F0}$ $\displaystyle = \dfrac{0.075}{(\log_{10} R_{e} - 2 ){}^2}$

(ITTC 1957 frictional coefficient line )

$\displaystyle C_{T}$	$\displaystyle = \dfrac{R_{T}}{\frac{1}{2} \rho U^2 S_{0}}, \quad C_{F} = \dfra... ...1}{2} \rho U^2 S_{0}}, \quad C_{P} = \dfrac{R_{P}}{\frac{1}{2} \rho U^2 S_{0}}$
$\displaystyle C_{F0}$	$\displaystyle = \dfrac{0.075}{(\log_{10} R_{e} - 2 ){}^2}$
	(ITTC 1957 frictional coefficient line )